Aptitude and Reasoning Questions

Q:

An exhibition was conducted for 4 weeks. The number of tickets sold in 2nd workweek was increased by 20% and increased by 16% in the 3rd workweek but decreased by 20% in the 4th workweek. Find the number of tickets sold in the beginning, if 1392 tickets were sold in the last week ?

A) 1124 B) 1420
C) 1345 D) 1250
 
Answer & Explanation Answer: D) 1250

Explanation:

Let initially 'X' ticket has been sold.
So now in 2nd week 20% increases, so
=> X x 120/100
In 3rd week 16% increases, so
=> X x (120/100) x (116/100)
In 4th week 20% decrease, so
=> X x (120/100) x (116/100) x (80/100) = 1392
X = 1250.

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Filed Under: Percentage
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Q:

 

Based on the given data, the total percentage of literates in the four cities together, round to one decimal, is

 

A) 55 B) 55.7
C) 55.9 D) 55.8
 
Answer & Explanation Answer: D) 55.8

Explanation:
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Filed Under: Table Charts
Exam Prep: Bank Exams

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Q:

The average age of a class is 19 years. While the average age of girls is 18 and that of boys is 21. If the number of girls in the class is 16, Find the number of Boys in the class?

A) 12 B) 10
C) 8 D) 6
 
Answer & Explanation Answer: C) 8

Explanation:

Let the number of boys = x

From the given data,

=> [21x + 16(18)]/(x+16) = 19

=> 21x - 19x = 19(16) - 16(18)

=> 2x = 16

=> x = 8

Therefore, the number of boys in the class = 8.

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Q:

A and B invests Rs.10000 each, A investing for 8 months and B investing for all the 12 months in the year. If the total profit at the end of the year is Rs.25000, find their shares?

A) 10000 and 15000 B) 15000 and 10000
C) 5000 and 20000 D) 20000 and 5000
 
Answer & Explanation Answer: A) 10000 and 15000

Explanation:

As both A and B invest the same amounts, the ratio of their profits at the end of the year is equal to the ratio of the time periods for which they have invested.

 

Thus, the required ratio of their profits = A : B = 8 : 12 = 2 : 3.

 

Hence, share of A in the total profit = 2 x 25000/5 = Rs.10000

 

Similarly, share of B in the total profit = 3 x 25000/5 = Rs.15000

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Filed Under: Partnership
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Q:

Identify the diagram that best represents the relationship among the given classes.

 

Women, Trainer, Pilot

A) 1 B) 2
C) 3 D) 4
 
Answer & Explanation Answer: A) 1

Explanation:
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Filed Under: Logical Venn Diagram
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Q:

A son and father goes for boating in river upstream . After rowing for 1 mile son notices the hat of his father falling in the river. After 5 min he tells his father that his hat has fallen. So they turn round and are able to pick the hat at the point from where they began boating after 5min. Find the speed of river  in miles/hours ?

A) 4 mile/hr B) 6 mile/hr
C) 2 mile/hr D) 5 mile/hr
 
Answer & Explanation Answer: B) 6 mile/hr

Explanation:

Let the speed of river and boat be 'r' m/min and 'b' m/min.
so relative speed in upstream (b-r)m/min and in downstream (b+r)m/min.
Now in upstream distnce covered in 5 min is 5(b-r)miles
so total distnce covered => 1 + 5(b-r)miles in upstream
In downstream distance covered in 5min is 5(b+r)miles
Now 1 + 5(b-r) = 5(b+r)
1+5b-5r = 5b+5r
1 = 10r
r = 1/10 mile/min => 6 mile/hr.

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Filed Under: Time and Distance
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Q:

If a box contains 10 bulbs,of which just three are defective. If a random sample of five bulbs is drawn, find the probability that the sample contains no defective bulbs.

A) 5/12 B) 7/12
C) 3/14 D) 1/12
 
Answer & Explanation Answer: D) 1/12

Explanation:

Total number of elementary events = 10C5

 

Number of ways of selecting no defective bulbs i.e., 5 non-defective bulbs out of 7 is 7C5.

 

So,required probability =7C510C5 = 1/12.

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Q:

In how many ways can an animal trainer arrange 5 lions and 4 tigers in a row so that no two lions are together?

A) 2800 B) 2880
C) 2600 D) 3980
 
Answer & Explanation Answer: B) 2880

Explanation:

They have to be arranged in the following way :

                                                                    L  T  L  T  L  T  L  T  L

The 5 lions should be arranged in the 5 places marked ‘L’.

This can be done in 5! ways.

The 4 tigers should be in the 4 places marked ‘T’.

This can be done in 4! ways.

Therefore, the lions and the tigers can be arranged in 5!´ 4! ways = 2880 ways.

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