Aptitude and Reasoning Questions

Let y be the total number of loaves
a be the remaining loaves after 1st thief
b be the remaining loaves after 2nd thief
and c, d..so on after 3 and 4 th
e = 0 be the remaining loaves after 5th thief

a = y - (y/2 + 1/2)
= y/2 - 1/2

b = a - (a/2 + 1/2)
= a/2 - 1/2

c = b - (b/2 + 1/2)
= b/2 - 1/2

d = c - (c/2 + 1/2)
= c/2 - 1/2

e = d - (d/2 + 1/2)
= d/2 - 1/2
we know that, e = 0,
thus by substitution, we get
d = 1
c = 3
b = 7
a = 15
y = 31
Therefore total number of bread loaves in bakery was 31.

Given number of girls are twice that of boys.

--> G=2B and G+B = 60 

Therefore,  G=40 and B= 20

Given Laxmi ranked 27th from the top and 9 boys are ahead of Laxmi.

Therefore, There are 17 girls ahead of Laxmi. 

Therefore, Number of girls who ranked after Laxmi = 40 - (17+1) = 22.

FRIEND : FPIBNZ

Follows a pattern that,

F - F

R- second letter to left of R i.e, P

I - I

E - Third letter to left of E i.e, B

N - N

D - Fourth letter to left of D i.e, Z

Similarly, for PATRON 

P - P

A -  second letter to left of A i.e, Y

T - T

R - Third letter to left of R i.e, O

O - O

N - Fourth letter to left of N i.e, J

PATRON : PYTOOJ

Therefore, FRIEND : FPIBNZ :: PATRON : PYTOOJ

The given series consists of squares of consecutive prime numbers
2*2, 3*3, 5*5,  . . . . , 11*11, 13*13, 17*17

A takes 24 days to complete a work.
B is 20% more efficient than A,
hence B will take (24*100)/120 = 20 days.
C takes (20+10) = 30 days.
Time taken by A & C in completing the work = (24*30)/(24+30) = (24*30)/54 = 40/3 days.

Rate of leakage = 8.33% per hour

Net efficiency = 50 - (16.66 + 8.33)= 25%

Time required = 100/25 = 4 hours

Let Anushka age = X
Charu latha 12 yrs older than Anushka so Charu latha age = x+12
Kajal is thrice as old as Anushka so Kajal age = 3x
The ages of Anushka, Kajal and Charu latha together are 57 years
i.e x + (x+12) + 3x = 57
=> 5x = 45
:- x = 9
Anushka age = 9
Kajal age = 3x = 27
Charu latha age = x+12 = 21