Aptitude and Reasoning Questions

After day 1, A finishes 1/9 of the work.

After day 2, B finishes 1/7 more of the total work. (1/9) + (1/7) is finished.

After day 3, C finishes 1/5 more of total work. Total finished is 143/315.

So, after day 6, total work finished is 286/315.

Now remaining work =  29 /315

On day 7, A will work again 

Work will be completed on day 7 when A is working. He must finish 29/315 of total remaining work.

Since he takes 9 days to finish the total task, he will need 261/315 of the day. 

Total days required is 6 + (261/315) days.

Here the LCM of 54, 60 is

=> 2 x 3 x 3 x 3 x 10

= 6 x 9 x 10

= 54 x 10

= 540.

This is the number of permutations of five things taken all at a time.

Therefore, answer = 5P5 = 120 ways

Suppose A, B and C take x, x/2 and x/3 respectively to finish the work. 

Then, (1/x + 2/x + 3/x) = 1/2 

=> 6/x = 1/2      => x = 12 

So, B takes 6 hours to finish the work.

Shalini is Meena's step-daughter means Shalini is the daughter of the other wife of Rohan. 

So, Shalini is the daughter of Lakshmi or Lakshmi is the mother of Shalini 

ja ke mo pe    =>  at a frog's leap          --------(i)

mo la ki so     =>  take a leapahead       --------(ii)

re bo na ja     =>  insects are frog's diet  --------(iii)

From (i) and (ii),   a leap  =>  ki mo       --------(iv)

From (i) and (iii),  frog's   =>   ja           ---------(v)

From (i), (iv) and (v),  'at' => pe

K x 3/8 = 141 => K = 376

376 x 32.08/100 = 120