Aptitude and Reasoning Questions

6P4 = 6! / (6-4)! = 360

Clearly, in the given arrangement, the numbers have been arranged in descending order in a sequence, altering the position of only one number in each step

Input       : 03   31   43   22   11   09

Step I      : 43   03   31   22   11   09
Step II     : 43   31   03   22   11   09
Step III   : 43   31   22   03   11   09
Step IV   : 43   31   22   11   03   09
Step V    : 43   31   22   11   09   03

Area to be plastered= [2(l + b) x h] + (l x b)

= [2(25 + 12) x 6] + (25 x 12)

= (444 + 300)

= 744 sq.m

Cost of plastering = Rs.744 x (75/100)

Let 'A' be the cost price of property P1.

Then from the given data, the selling price of P1 = Rs. 1,00,000

He got 20% loss on selling P1

$$\begin{gathered} ⇒A - 20A100 = 100000 \\ ⇒A = 1,25,000 \end{gathered}$$

Therefore, the amount he lossed on selling P1 = 25,000

As ge he got no loss or gain on sale of P1 and P2, the gain on selling P2 = 25,000

But the selling price of P2 = 1,00,000 => Cost price of P2 = 75,000

Hence, the profit percentage on P2 = GainCPx 100 = 2500075000x100 = 1003= 33.33%

Let the 6 digits of the required 6 digit number be abcdef

Then, the number to be odd number the last digit must be odd digit i.e 3, 5, 7 or 9

The first digit cannot be ‘0’ => possible digits = 3, 5, 7, 2, 6, 8

Remaining 4 places can be of 6 x 5 x 4 x 3 ways

This can be easily understood by

Therefore, required number of ways = 6 x 6 x 5 x 4 x 3 x 4 = 36 x 20 x 12 = 720 x 12

= 8640 ways.

Let
P's capital = p,
Q's capital = q and
R's capital = r.
Then

6p = 8q = 12r
=> 3p = 4q = 6r
=>q = 3p/4
r = 3p/6 = p/2
P : Q : R = p : 3p/4 : p/2
= 4 : 3 : 2
R's share = 4650 * (2/9) = 150*6 = Rs. 1033.33.

Here Ammeter is used for measuring Current whereas Odometer is used to measure Speed.