Aptitude and Reasoning Questions

Given that,

1st train speed = 62 km/hr 

2nd train speed  = 44 km/hr

Hence the relative speed of two trains is : 62-44 = 18 km/hr = 18×518 m/s = 5 m/s.

There fore, the first train crosses the second train i.e (85+75)mts of distance with a speed of 5m/s in, 

time = distancespeed = 85+755 = 32 sec.

From the given data,

                       Day      Capacity

A              ->    12          2

B              ->     8           3             2

A + B + C ->     2            12

=> Capacity of C = 12 - 5 = 7

Ratio of capacity of A : B : C = 2 : 3 : 7

Difference of wages of C & B = 4/5 x 1540

= 4 x 308 = Rs. 1232

From the given data,

Ratio of capital = 12000 : 14400 = 5 : 6

Required Difference = 

$$\begin{gathered} 6 - 56 + 5 88100 x 7500 + 12100 x 7500 \\ = 111 x 88 x 75 + 12 x 75 \\ = 600 + 900 \\ = 1500 \end{gathered}$$

Cost of Rs. 100 stock  = Rs. (100+4) = Rs.104

Cost of Rs. 4500 stock =Rs.104100×4500 = Rs. 4680

Let 'd' be the distance between A and B
K -time = d/10 + d/9 = 19d/90 hours
L -time = 2d/12 = d/6 hours
We know that, 10 min = 1/6 hours
Thus, time difference between K and L is given as 10 minutes.
=> 19d/90 - d/6 = 1/6
=> (19d-15d)/90 = 1/6
=> 4d/90 = 1/6
Thus,
d= 15/4 km = 3.75 km.

hence the distance between A and B is 3.75 km.

-5-----------------------5-------------------20

5-(-5) = 10

20-5= 15

Ratio of cost price of book1 and book2 = 3:2 

Then cost price of book 1 is given by

(3/5) x 100 = Rs. 60.

Given,

 5sinx + 12cosx ≥ -r 

⇒13513sin x + 1213cos x ≥ -rcosx) ≥ -r 

513= cosA => sinA =1213

=> 13(sinx cosA + sinA cosx) ≥ -r

=> 13(sin(x + A)) ≥ -r

we know that , -1 ≤ sin (angle) ≤ 1

=> 13sin (x + A) ≥ -13 ⇒rmin =13