Aptitude and Reasoning Questions

Q:

Three different containers contain 1365 litres, 1560 litres and 1755 litres of mixtures of milk and water respectively. What biggest measure that can measure all the different quantities exactly ?

A) 37 lit B) 97 lit
C) 129 lit D) 195 lit
 
Answer & Explanation Answer: D) 195 lit

Explanation:

From the given data,

containers contain mixtures of milk and water as 1365 lit, 1560 lit and 1755 lit.

 

Biggest measure that can measure all these different quantities exactly can be given by

HCF of (1365, 1560, 1755) 

That can be found as 

 

HCF of 1365, 1755 = 195

Now, HCF of 195 and 1560 = 195

 

Hence, biggest measure that can measure all the given different quantities exactly is 195 lit.

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Filed Under: HCF and LCM
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11 5921
Q:

There is an unprecedented increase in migration of villagers to urban areas as repeated crop failure has put them into precarious financial situation.

 

Courses of Action:

I. The villagers should be provided with alternate source of income in their villages which will make them stay put.

II. The migrated villagers should be provided with jobs in the urban areas to help them survive.

A) Only I follows B) Only II follows
C) Neither I nor II follows D) Both I and II follow
 
Answer & Explanation Answer: A) Only I follows

Explanation:

Clearly, increased migration would add to the burden on city's infrastructure. So, attempts should be made to make the villagers feel comfortable in the villages itself. So, only course I follows.

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Q:

The average of ages of threee persons is 60 years . Those ages are in the proportion of 1:2:3. what is the age of the youngest one among them?

Answer

Suppose the ages of three persons are x, 2x, 3x years respectively 





Hence, age of youngest person = x = 30 years.

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Subject: Problems on Ages

3 5918
Q:

A boat can move 5 km/hr in still water. If the river is running at 1 km/hr, it takes it 75 min to move to a place and back. How far is the place?

A) 3 kms B) 5 kms
C) 6 kms D) 4 kms
 
Answer & Explanation Answer: A) 3 kms

Explanation:

Let the place be at a distance of 'd' kms

From the given data,

d5 - 1 + d5 + 1 = 7560 kmsd4 + d6 = 54

5d/12 = 5/4 => d = 3 kms.

 

Hence, the place is 3 kms far.

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Filed Under: Boats and Streams
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21 5917
Q:

Find the odd one out of the following words ?

A) cruise B) crusade
C) expedition D) campaign
 
Answer & Explanation Answer: A) cruise

Explanation:

Cruise = a sea voyage for pleasure. All other words are related to ‘journey on land, sea with an aim’.

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Filed Under: Analogy
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3 5915
Q:

3, 6, 17.5, 64.75, ?

A) 304.587 B) 295.875
C) 115.246 D) 101
 
Answer & Explanation Answer: B) 295.875

Explanation:

3

3 x 1.5 + 1.5 = 6

6 x 2.5 + 2.5 = 17.5

17.5 x 3.5 + 3.5 = 64.75

64.75 x 4.5 + 4.5 = 295.875

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Filed Under: Number Series
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24 5913
Q:

LCD of 12 and 18

A) 36 B) 42
C) 12 D) 6
 
Answer & Explanation Answer: A) 36

Explanation:

  LCD is nothing but Lowest or Least Common Denominator

 

Here LCD of 12 and 18 means LCD of two fractions with denominators 12 and 18 respectively.

 

Therefore, LCM of 12 & 18 = 6 x 3 x 2 = 36 

 

      •  How to calculate LCD ::


The lowest common denominator or least common denominator (LCD) is the least common multiple (LCM) of the denominators of a set of fractions.

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Filed Under: HCF and LCM
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27 5913
Q:

The length, breadth and height of a room are in the ratio 7:3:1. If the breadth and height are doubled while the length is halved, then by what percent the total area of the 4 walls of the room will be increased  ?

A) 90% B) 88%
C) 85% D) 84%
 
Answer & Explanation Answer: A) 90%

Explanation:

Let length, breadth and height of the room be 7, 3, 1 unit respectively.

Area of walls = 2(l+b)xh = 2(7+3)x1 = 20 sq. unit.

Now, length, breadth and height of room will become 3.5, 6 and 2 respectively. 

Area of walls = 2(l+b)xh = 2(3.5+6)x2 = 38 sq. unit. 

% Increase in the area of walls = (38-20)x100/20 = 90%.

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Filed Under: Area
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