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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

If rupee two produces rupees eleven over a period of 30 years, find the rate of simple interest ?

A) 17.25 % B) 18.14 %
C) 18.33 % D) 17.35 %
 
Answer & Explanation Answer: C) 18.33 %

Explanation:

We know that I = PTR/100

11 = (2x30xR)/100

R = 18.333 %

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Filed Under: Simple Interest
Exam Prep: AIEEE , Bank Exams , CAT , GATE
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3 4961
Q:

Choose the synonym of 'Maelstrom' from the following given words ?

A) Congregation B) Thunder
C) Miracle D) Turmoil
 
Answer & Explanation Answer: D) Turmoil

Explanation:

'Maelstrom' refers to a violent and confused state. The word closest in meaning would be 'turmoil', which also means a state of great disturbance.

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Filed Under: Analogy
Exam Prep: AIEEE , Bank Exams , CAT , GATE , GRE
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5 4961
Q:

Group the given figures into three classes using each figure only once.

   9_(1)1484718122.png image

A) 1,5,9 ; 2,7,8 ; 3,4,6 B) 2,4,9 ; 6,7,8 ; 1,3,5
C) 3,7,8 ; 4,5,9 ; 1,2,6 D) 1,5,6 ; 4,7,8 ; 2,3,9
 
Answer & Explanation Answer: B) 2,4,9 ; 6,7,8 ; 1,3,5

Explanation:

2, 4, 9 have two similar elements intersecting each other.
6, 7, 8 have two different elements one placed inside the other.
1, 3, 5 have two different elements intersecting each other.

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Filed Under: Grouping of Images
Exam Prep: AIEEE , Bank Exams , CAT
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5 4957
Q:

Laxmi and Prasanna set on a journey. Laxmi moves northwards at a speed of 20kmph and Prasanna moves southward at a speed of 30 kmph. How far will be Prasanna from Laxmi after 60 minutes ?

A) 24 km B) 50 km
C) 42 km D) 30 km
 
Answer & Explanation Answer: B) 50 km

Explanation:

We know 60 min = 1 hr
Total northward Laxmi's distance = 20kmph x 1hr = 20 km
Total southward Prasanna's distance = 30kmph x 1hr = 30 km
Total distance between Prasanna and Laxmi is = 20 + 30 = 50 km.

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Filed Under: Time and Distance
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Analyst , Bank Clerk , Bank PO

3 4954
Q:

If two cards are taken one after another without replacing from a pack of 52 cards. What is the probability for the two cards be Ace ?

A) 51/1221 B) 42/221
C) 1/221 D) 52/1245
 
Answer & Explanation Answer: C) 1/221

Explanation:

Total Combination of getting a card from 52 cards = C152

Because there is no replacement, so number of cards after getting first card= 51

Now, Combination of getting an another card= C151


Total combination of getting 2 cards from 52 cards without replacement= (C152×C151) 


There are total 4 Ace in stack. Combination of getting 1 Ace is = C14

 

Because there is no replacement, So number of cards after getting first Ace = 3


Combination of getting an another Ace = C13

Total Combination of getting 2 Ace without replacement=C14×C13

Now,Probability of getting 2 cards which are Ace =C14×C13C152×C151 = 1/221.

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Filed Under: Permutations and Combinations
Exam Prep: CAT , Bank Exams , AIEEE
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5 4947
Q:

There are 3 sections with 5 questions each. If four questions are selected from each section, the chance of getting different questions is ?

A) 1000 B) 625
C) 525 D) 125
 
Answer & Explanation Answer: D) 125

Explanation:

Methods for selecting 4 questions out of 5 in the first section = 5 x 4 x 3 x 2 x 1/4 x 3 x 2 x 1 = 5. Similarly for other 2 sections also i.e 5 and 5


So total methods = 5 x 5 x 5 = 125.

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Filed Under: Permutations and Combinations
Exam Prep: GRE , GATE , CAT , Bank Exams , AIEEE
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4 4944
Q:

Complete the Figure X from the given alternatives 1, 2, 3 and 4.

 

 

A) 1 B) 2
C) 3 D) 4
 
Answer & Explanation Answer: B) 2

Explanation:
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Filed Under: Pattern Completion
Exam Prep: Bank Exams

0 4942
Q:

If - means ÷ , + means x , ÷ means - , x means +, then which of the following equations is correct?

A) 43 x 7 ÷ 5 + 4 - 8 = 25 B) 48 ÷ 5 + 8 x 10 - 2 = 03
C) 36 x 4 - 12 + 5 ÷ 3 = 420 D) 42 + 5 ÷ 6 x 8 - 3 = 28
 
Answer & Explanation Answer: B) 48 ÷ 5 + 8 x 10 - 2 = 03

Explanation:
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Filed Under: Coding and Decoding

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