Aptitude and Reasoning Questions

Q:

Savita sold an item for 6,500 and incurred a loss of 20%. At what price should she have sold the item to have gained a profit of 20%?

A) 10,375 B) 9,750
C) 8,125 D) Cannot be determined
 
Answer & Explanation Answer: B) 9,750

Explanation:

C.P of article = 6500 * (100/80) = Rs. 8125 S.P for a gain of 20% = (8125*120)/100 = Rs. 9750

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Filed Under: Profit and Loss

3 3267
Q:

DI.

What is the difference between the number of uneducated females in city P and that of uneducated males in city S ?

A) 9 lakhs B) 6 lakhs
C) 3 lakhs D) 2 lakhs
 
Answer & Explanation Answer: A) 9 lakhs

Explanation:

Educated females in city P = 25 lakhs

Uneducated females in city P = 30 - 25 = 5 lakhs

Educated males city S = 21 lakhs

Educated males in city S = 35 - 21= 14 lakhs

Required difference = 14 - 5 = 9 lakhs

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Filed Under: Table Charts
Exam Prep: GATE , CAT , Bank Exams , AIEEE
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14 3266
Q:

Manu invested an amount of Rs. 14800 at the rate of 7% per annum. After how many years will she obtain a simple interest of Rs.15800?

A) 16.75 yrs B) 15.25 yrs
C) 14 yrs D) 13.5 yrs
 
Answer & Explanation Answer: B) 15.25 yrs

Explanation:

We know that,

I = PTR/100

ATQ,

15800 = 14800 x T x 6/100

T = 15800/148x7

T = 15800/1036

T = 15.25 yrs.

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Filed Under: Simple Interest
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10 3262
Q:

In three coloured boxes - Red, Green and Blue, 108 balls are placed. There are twice as many balls in the green and red boxes combined as there are in the blue box and twice as many in the blue box as there are in the red box. How many balls are there in the green box ?

A) 76 B) 54
C) 64 D) 48
 
Answer & Explanation Answer: B) 54

Explanation:

Let R, G and B represent the number of balls in red, green and blue boxes respectively.

Then, .

R + G + B = 108 ...(i),

G + R = 2B ...(ii)

B = 2R ...(iii)

From (ii) and (iii), we have G + R = 2x 2R = 4R or G = 3R.

Putting G = 3R and B = 2R in (i), we get:

R + 3R + 2R = 108 6R = 108 R = 18.

Therefore Number of balls in green box = G = 3R = (3 x 18) = 54.

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Filed Under: Arithmetical Reasoning
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2 3260
Q:

X and Y together can do a piece of work in 30 days. Y and Z together can do the work in 20 days. X starts the work and works for 15 days then Y takes that work and works for 27 days. Finally Z finishes the remaining work in 9 days. In how many days Y alone can complete the entire work?

 

A) 60 B) 45
C) 50 D) 65
 
Answer & Explanation Answer: A) 60

Explanation:
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Filed Under: Time and Work
Exam Prep: Bank Exams

3 3255
Q:

Divide Rs. 80 in the proportion of 3:6:7.

A) Rs. 10, Rs. 35, Rs. 40 B) Rs. 15, Rs. 30, Rs. 35
C) Rs. 15, Rs. 35, Rs.30 D) Rs. 10, Rs. 40, Rs. 35
 
Answer & Explanation Answer: B) Rs. 15, Rs. 30, Rs. 35

Explanation:

3/16 X 80, 6/16 X 80, 7/16 X 80
⇒ 15, 30, 35

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Filed Under: Ratios and Proportions
Exam Prep: Bank Exams

7 3253
Q:

Concept of Nehative Work

A tub can be filed in 20 minutes but there is a lekage in it which can empty the full tub in 60 minutes. In how many minutes it can be filled?

Answer

Filling efficiency = 5%        


Emptying efficiency = 1.66%  


Net efficiency = 5-1.66 = 3.33%


Therefore, Required time to fil the tub =100/3.33= 30 minutes

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Subject: Time and Work

2 3252
Q:

In the following question, two equations numbered 1 and 2 are given. You have to solve both the equations and determine the relation between a and b.

1.  5a2-18a+9=0

2.  3b2+5b-2=0

A) a >= b B) a <= b
C) a < b D) a > b
 
Answer & Explanation Answer: D) a > b

Explanation:

From solving 1 and 2 we get,

 

1.

5a(a-3)-3(a-3) = 0

 

(5a-3)(a-3) = 0

 

a = 3 or 3/5

 

2. 

 

3b(b+2)-1(b+2) = 0

 

b = -2 or b = 1/3

 

Here when a = 3, a > b for b = -2 and b = 1/3

 

when a = 3/5. a > b for b = -2 and b = 1/3.

 

Hence, it is clear that a > b. 

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Filed Under: Statement and Conclusions
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4 3250