AIEEE Questions

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The smallest unit of data storage in a computer is called Bit (Binary Digit). Half a byte (four bits) is called a Nibble.

1 bit (binary digit) = the value of 0 or 1

8 bits = 1 byte

1024 bytes = 1 kilobyte

1024 kilobytes = 1 megabyte

1024 megabytes = 1 gigabyte

1024 gigabytes = 1 terabyte

1024 terabytes = 1 petabyte

Hence, Computer storage units smallest to largest i.e, in ascending order is

 1 bit  <  1 byte  <  1 KB  <  1 MB  <  1 GB  <  1TB  <  1 PB.

In a chemical reaction, substances (elements or compounds) called reactants are changed into other substances (compounds or elements) called products. Hence, reactants are those which start the chemical reaction.

For example:

1. In the burning of natural gas, methane (CH4) and oxygen (O2) are the reactants in the chemical reaction. are the substances formed by a chemical reaction. In the burning of natural gas, carbon dioxide (CO2) and water (H2O) are the products formed by the reaction.

2. H2+O2 ----> H2O

Here H2 & O2 are called Reactants and H2O is called Product.

A Sound wave needs a medium for propogation. Hence, Sound cannot travel through a vacuum.

A vacuum is an area without any air, like space. So sound cannot travel through space because there is no matter for the vibrations to work in.

In computing, the expansion card or board or accessory card is a printed circuit board that can be inserted into an electrical connector or expansion slot, on a computer motherboard, to add functionality to a computer system via the expansion bus.

∆Tf = kf.m 

for ethylene glycol in aq. solution

 $$\begin{gathered} ∆Tf = kf wmol.wt × 1000wt. of solvent \\ 6 = 1.86 x w x 100062 x 4000 \end{gathered}$$

=> w = 800 g

So, the weight of solute should be more than 800 g.

 ZA = 88  ; ZB = 52

So formula of compound is AB52 

i.e., A2B5.

K's work in a day(1st day) = 1/30
L's work in a day(2nd day)= -1/60(demolishing)
hence in 2 days, combined work= 1/30 - 1/60 =1/60
since both works alternatively, K will work in odd days and L will work in even days.
1/60 unit work is done in 2 days
58/60 unit work will be done in 2 x 58 days = 116 days
Remaining work = 1-58/60 = 1/30
Next day, it will be K's turn and K will finish the remaining 1/30 work.
hence total days = 116 + 1 = 117.

There is two sequence.
S(odd) P(Even) I(odd) D(even) E(odd) R(even) M(odd) A(even) N(odd)
For odd sequence, we want to write next alphabet of that
and for even, we want to write previous alphabet of that.

TOJCFQNZO is the Answer.