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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

A woman says, "If you reverse my own age, the figures represent my husband's age. He is, of course, senior to me and the difference between our ages is one-eleventh of their sum." The woman's husband age is ?

A) 45 B) 24
C) 42 D) 54
 
Answer & Explanation Answer: D) 54

Explanation:

By trial and error method from the given options,

as 54 - 45 =  (1/11) x (45+54)  = 99/11  = 9

Hence this satisfies the given conditions.

Then the woman's husband age is 54.

 

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Filed Under: Problems on Ages
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10 8415
Q:

Find the length of the altitude of an equilateral triangle of side  33cm.

A) 4.5 B) 3.5
C) 2.5 D) 6.5
 
Answer & Explanation Answer: A) 4.5

Explanation:

Let the length of the altitude be h.
Then, h = a32   = 33 × 32 = 4.5

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Filed Under: Area
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3 8411
Q:

934+7217-9115=?

A) 7 + 719/1020 B) 9 + 817/1020
C) 9 + 719/1020 D) 7 + 817/1020
 
Answer & Explanation Answer: D) 7 + 817/1020

Explanation:

given sum =9+34+7+217-9+115

 

9+7+9+34+217-115

 

=> 7+765+120-681020=>7+8171020 

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Filed Under: Numbers

4 8401
Q:

A bill falls due in 1 year.The creditor agrees to accept immediate payment of the half and to defer the payment of the other half for 2 years.By this arrangement ins Rs.40.what is the amount of the bill,if he money be worth 12.5%?

A) 1200 B) 3000
C) 3600 D) 1300
 
Answer & Explanation Answer: C) 3600

Explanation:

Let the sum be Rs. x. Then,   

x2+x2×100100+252×2-x×100100+252×1 = 40  

(x/2)+(2x/5)-(8x/9) = 40  

x=3600.  

Therfore, amount of bill=Rs. 3600.

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Filed Under: True Discount

5 8399
Q:

A restaurant offers a new promotion of 20% off the original price of cakes, which is Rs. 12. Before the promotion 250 cakes were sold each day. After the promotion, the sale of cakes increases an average of 18% more per day. How much more or less does the restaurant make each day in cakes sales after the promotion?

A) Rs. 185 less B) Rs. 202 more
C) Rs. 175 more D) Rs. 168 less
 
Answer & Explanation Answer: D) Rs. 168 less

Explanation:

Cost of each cake P1 & P2 = Rs. 12

Offer decrease in % = 20%

Increase in sale per day (Q2) = 250 - 18%

Total quantity per day (Q1) = 250

Hence, required change total revenue

TR = P2Q2 - P1Q1 = (12 x 0.8 x 250 x 1.18) -  (12 x 250) = - Rs.168.

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Filed Under: Percentage
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15 8395
Q:

A train 900 m long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 min, then the length of the tunnel is ?

A) 400 m B) 300 m
C) 500 m D) 600 m
 
Answer & Explanation Answer: A) 400 m

Explanation:

Speed = 78 x 5/18 = 65/3 m/sec.
Time = 1 min = 60 sec.
Let the length of the train be x meters.
Then, (900 + x)/60 = 65/3
x = 400 m.

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Filed Under: Problems on Trains
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7 8395
Q:

At a casino in mumbai, there are three tables A, B and C. The payoffs at A is 10:1, at B is 20:1 and at C is 30:1. If a man bets Rs 200 at each table and win at two of the tables, what is the maximum and minimum difference between his earnings can be?

A) Rs.2500 B) Rs.2000
C) Rs.4000 D) None of these
 
Answer & Explanation Answer: C) Rs.4000

Explanation:

Maximum earning will be only when he will won on the maximum yielding table.

     A ----> 10:1

     B ----> 20:1

     C ----> 30:1

 i.e, he won on B and C but lost on A

 20 x 200 + 30 x 200 -1 x 200 = 9800

 minimum earning will be when he won on  table A and B and lose on that table 3.

 

Therefore, 10 x 200 + 20 x 200 - 1 x 200  =  6000-200 = 5800

Therefore, Difference= 9800 - 5800 = 4000

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Filed Under: Ratios and Proportions

12 8393
Q:

The number of ways in which six boys and six girls can be seated in a row for a photograph so that no two girls sit together is  ?

A) 2(6!) B) 6! x 7
C) 6! x ⁷P₆ D) None
 
Answer & Explanation Answer: C) 6! x ⁷P₆

Explanation:

We can initially arrange the six boys in 6! ways.
Having done this, now three are seven places and six girls to be arranged. This can be done in ⁷P₆ ways.

Hence required number of ways = 6! x ⁷P₆

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Filed Under: Permutations and Combinations
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6 8392