Aptitude and Reasoning Questions

Q:

The average marks of a student in 7 subjects is 85. His average marks in 6 subjects except English is 83. What is his marks in English ?

A) 97 B) 98
C) 92 D) 93
 
Answer & Explanation Answer: A) 97

Explanation:

Marks in English  = 85×7 – 83×6

= 595 – 498

= 97

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Filed Under: Average
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Q:

What is the ratio between the volumes of a cylinder and cone of the same height and of the same diameter

A) 2:1 B) 3:1
C) 4:1 D) 5:1
 
Answer & Explanation Answer: B) 3:1

Explanation:

Volume of cylinder / Volume of cone = 3/1

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Filed Under: Volume and Surface Area
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Q:

On a ruler's tombstone, it is said that one sixth of his life was spent in childhood and one twelfth as a teenager. One seventh of his life passed between the time he became an adult and the time he married; five years later, his son was born. Alas, the son died four years before he did. He lived to be twice as old as his son did. How old did the ruler live to be ?

A) 84 years B) 72 years
C) 82 years D) 64 years
 
Answer & Explanation Answer: A) 84 years

Explanation:

Let the age of ruler is x so that of son = x/2 (given)
Now according to the given condition
(x/6) + (x/12) + (x/7) + 5 + (x/2) + 4 = x
=> x = 84

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Filed Under: Problems on Ages
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Q:

From a container of wine, a thief has stolen 15 litres of wine and replaced it with same quantity of water. He again repeated the same process. Thus, in three attempts the ratio of wine and water became 343 : 169. The initial amount of wine in the container was:

A) 75 litres B) 100 litres
C) 150 litres D) 120 litres
 
Answer & Explanation Answer: D) 120 litres

Explanation:

wine(left)wine(added) = 343169

 

It means  wine(left)wine(initial amount) = 343512    (since 343 + 169 = 512)

  

Thus,  343x = 512x1 - 15k3

 

 343512 = 783 = 1 - 15k3

 

 1-15k=78=1-18

  

Thus the initial amount of wine was 120 liters.

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Filed Under: Alligation or Mixture
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29 8466
Q:

In the following question, four groups of three numbers are given. In each group the second and third number are related to the first number by a Logic/Rule/Relation. Three are similar on basis of same Logic/Rule/Relation. Select the odd one out from the given alternatives.

 

A) (31, 34, 37) B) (43, 45, 48)
C) (39, 42, 45) D) (7, 10, 13)
 
Answer & Explanation Answer: C) (39, 42, 45)

Explanation:
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Filed Under: Odd Man Out
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Q:

A dishonest shopkeeper professes to sell his groceries at his cost price but uses a false weight of 900 grams for each kilogram. Find his gain percentage.

A) 91/9 % B) 100/9%
C) 100/11 % D) 95/9%
 
Answer & Explanation Answer: B) 100/9%

Explanation:

Shopkeeper sells at CP using weight of 900 gm instead of1 kg

So, 1000gm –900 gm = 100gm

⇒100/900 X 100

⇒100/9 %

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Filed Under: Profit and Loss
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Q:

The bankers discount and the true discount of a sum at 10% per annum simple interest for the same time are Rs.100 and Rs.80 respectively. What is the sum and the time?

A) Sum = Rs.400 and Time = 5 years B) Sum = Rs.200 and Time = 2.5 years
C) Sum = Rs.400 and Time = 2.5 years D) Sum = Rs.200 and Time = 5 years
 
Answer & Explanation Answer: C) Sum = Rs.400 and Time = 2.5 years

Explanation:

BD = Rs.100

TD = Rs.80

R = 10%

 

F=BD×TDBD-TD=100×80100-80=Rs.400 

 

BD = Simple interest on the face value of the bill for unexpired time= FTR/100

 

100=400×T×10100

=> T = 2.5 years

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Filed Under: Banker's Discount

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Q:

In what time will Rs.1000 become Rs.1331 at 10% per annum compounded annually?

A) 2years B) 3years
C) 4years D) 5years
 
Answer & Explanation Answer: B) 3years

Explanation:

Principal = Rs.1000;

Amount = Rs.1331;

Rate = Rs.10%p.a.

 

Let the time be n years.Then

[1000(1+10/100)Λn;]

= 1331.

= (1331/1000)

= (11/10)³

 

Therefore n = 3 years.

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Filed Under: Compound Interest
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