Aptitude and Reasoning Questions

Let the least value of the prize = Rs. x

Then the next value of the prize is x+30 , x+60, x+90, ....x+240.

Given total amount of cash prizes = Rs.1890

--> x + (x+30) + (x+60) + (x+90) + ....+ (x+240) = 1890

--> 9x + (30 + 60 + 90 + 120 + 150 + 180 + 210 + 240) = 1890

--> 9x + 30(1 + 2 + 3 + 4....+ 8) = 1890

--> 9x + 30(36) = 1890

--> 9x = 810 --> x=90

Hence the least value of the prize x=90

Let the present ages be K,M

Given K/M = 4/5

5K - 4M = 0 ......(1)

Also given that,

M - (K + 5) = 3

M - K = 8 .........(2)

Then, by solving (1) & (2)

M = 40 yrs and K = 32 yrs

Hence, Total of ages = 40 + 32 = 72 yrs

Difference of ages = 40 - 32 = 8 yrs.

Using the letters A, L, W

only one meaningful English word can be formed i.e, LAW

No other words can be formed.

FV
= $1000(1.04)(1.045)(1.05)(1.055)(1.06) =
$1276.14

 the maturity value of the regular GIC is

 FV =
$ 1000 x 1.055=
$1276.28

3000 – 3 = 2997

5% - 2% = 3%
=> 3% ------ 5 million bags
100% ---- ?
=> 166 2/3 million bags.

From statement A, we know that Pipe A can fill the tank in 40 hours. However, this information is not sufficient as we do not have the data for Pipe B. Hence, statement A alone cannot answer the given question.

From statement B, we know that Pipe B is one third as efficient as pipe A. However, we do not know the rate at which Pipe A fills the tank. Hence, we will not be able to find the rate at which Pipe B fills the cistern. Therefore, statement B alone is not sufficient to answer the question.

Now, if we combine the two statements, we know that Pipe A take 40 hours to fill the cistern.
Pipe B takes 120 hours to fill the cistern.

If they worked alternately, then either Pipe A could have started the cycle or Pipe B could have started the cycle.

If Pipe A started the sequence of filling alternately, then at the end of two hours, the two pipes together would have filled 1/40 + 1/120 = 1/30  th of the tank in an hour. Or the cistern will fill in 30 hours.

If Pipe B started the sequence, then at the end of 2 hours, the two pipes together would have filled 1/120 + 1/40 = 1/30 th of the tank in an hour. Or the cistern will fill in 30 hours.

As the answer obtained irrespective of which pipe started the sequence is the same, the correct answer is (3) - i.e., both the statement are sufficient to answer the question.

Let their ages one year  ago be 4x and 3x years

 Sum of their present ages =(4x +1+3x+1) = 16 years.