Aptitude and Reasoning Questions

Q:

What is the place value of 0 in 103?

A) 0 B) 100
C) 10 D) 103
 
Answer & Explanation Answer: A) 0

Explanation:

The place value of 0 in 103 is given by the product of digits place in the number and the digit.

Here 0 is in 10's place in 103

=> 0 x 10 = 0.

 

Hence, The place value of 0 in 103 = 0.

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Filed Under: Arithmetical Reasoning
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Q:

The total age of A and B is 12 years more than the total age of B and C. C is how many years younger than A ?

A) 12 B) 13
C) 14 D) 15
 
Answer & Explanation Answer: A) 12

Explanation:

(A+B) - (B-C) = 12 <=> A - C = 12.

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Filed Under: Problems on Ages

3 5239
Q:

Six friends A, B, C, D, E and F joined an institute in the year 1993 but on different days. Only E has joined after C and D. C joined immediately before A and immediately after B. F is not the first or the last person to join. D will not be in any corner.
Who is the first person joining the Institute?

A) E B) D
C) A D) B
 
Answer & Explanation Answer: D) B

Explanation:

The only possible way is BCAFDE
As D & F is not in any corner and E is after C and D. C is after B and before A
So the first person to join the institute is B

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6 5228
Q:

Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 4 or 15 ?

A) 6/19 B) 3/10
C) 7/10 D) 6/17
 
Answer & Explanation Answer: B) 3/10

Explanation:

Here, S = {1, 2, 3, 4, ...., 19, 20}=> n(s) = 20
Let E = event of getting a multiple of 4 or 15
=multiples od 4 are {4, 8, 12, 16, 20}
And multiples of 15 means multiples of 3 and 5
= {3, 6 , 9, 12, 15, 18, 5, 10, 15, 20}.
= the common multiple is only (15).
=> E = n(E)= 6
Required Probability = P(E) = n(E)/n(S) = 6/20 = 3/10.

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Filed Under: Probability
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6 5218
Q:

Which of the following could not be the lengths of the sides of a right angled triangle?

A) 3, 4, 5 B) 5, 12, 13
C) 8, 15, 17 D) 12, 15, 18
 
Answer & Explanation Answer: D) 12, 15, 18

Explanation:

Using Pythagoras theorem we can see that 122 + 152 is not equal to 182
Neither is 102 + 242 = 252

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Filed Under: Ratios and Proportions
Exam Prep: GRE

3 5218
Q:

Sharan and Mayukh, working together, can complete a task in 18 days. However, Mayukh works alone and leaves after completing 1/3 of the task. Then, Sharan takes over and completees the remaining work by himself. As a result, the duo could complete the task in 40 days. How many days would Sharan alone have taken to do the job if Mayuk' had worked faster than Sharan ?

A) 24 B) 45
C) 72 D) 30
 
Answer & Explanation Answer: B) 45

Explanation:
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Filed Under: Time and Work
Exam Prep: Bank Exams

16 5213
Q:

Total 100 members are writing exam. In that 48 members are writing first exam, 45 members are writing second exam and 38 members are writing third exam. 5 members are writing all the three exams. How many members are writing 2 exams ?

A) 26 B) 23
C) 27 D) 21
 
Answer & Explanation Answer: D) 21

Explanation:

Total number of exams written by 100 students = 48 + 45 + 38 = 131
Now let us say x members are writing only 1 exam, y members are writing only 2 exams, z members are writing only 3 exams.
Therefore, x + 2y + 3z = 131 also x + y + z = 100.
Given that z = 5. So x + 2y = 116 and x + y = 95.
Solving we get y = 21.
So 21 members are writing exactly 2 exams.

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Filed Under: Problems on Numbers
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6 5211
Q:

Rishi bought 30 kg of sugar at the rate of Rs. 9 per kg and 45 kg of sugar at the rate of Rs. 10 per kg. He mixed both type of sugar and sold the mixture at the rate of Rs. 9.75 per kg. What was his gain or loss in the selling of whole sugar?

A) Rs. 10.75 B) Rs. 11.25
C) Rs. 12 D) Rs. 13.50
 
Answer & Explanation Answer: B) Rs. 11.25

Explanation:

Total quantity of sugar = 45 + 30 = 75

Gain or loss can be calculated as

9.75 x 75 - (30 x 9 + 45 x 10)

= 731.25 - 720

= 11.25

 

Hence, in the overall transaction, Rishi got Rs. 11.25 gain.

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Filed Under: Profit and Loss
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