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Aptitude and Reasoning Questions

What are Different sections in Aptitude and Reasoning Question and Answers?

In this highly competitive world, Aptitude and reasoning tests are prominently important. Typically, there are multiple sections in this type of tests. Broadly they are: Verbal Reasoning(Mental Ability, Logical Deduction), Non-Verbal Reasoning, Quantitative Aptitude(Data interpretation, Arithmetic Ability).


Why Aptitude and Reasoning Questions?

Aptitude and Reasoning tests simply mean to measure or determine a person's ability in a particular skill or field of knowledge. These days most of Aptitude and Reasoning tests are in online format. With proper practice of these aptitude tests, They are easy to crack. Preparing for Aptitude and Reasoning tests will often avoid disappointments in Entrance Exams for various competitive exams and job interviews.


What type of questions are there in Aptitude and Reasoning tests?

Aptitude and Reasoning tests consists of various Arithmetic, Data interpretation, Diagrammatic and Psychometric question and answers. Though these tests seem confusing at first, with proper practice and applied logic, they are very easy to crack. Later, it becomes interesting to solve such puzzles. Most of these are based on a particular sequence, hence it is important to understand the sequence to solve the problem. Practicing these more and more will yield better results.

Popular Latest Rated
Q:

Choose the box that is similar to the box formed from the given sheet of paper (A).

121484628399.png image

      (A)

1211484628442.png image

A) Option 1,2 and 3 B) Option 1,2 and 4
C) Option 2 and 3 D) Option 2,3 and 4
 
Answer & Explanation Answer: D) Option 2,3 and 4

Explanation:

when a cube is formed by folding the sheet shown in fig. (A), then 22-11484628706.png image  is one of the faces of the cube and this face lies opposite to a blank face. Also, a face bearing a square lies opposite to another blank face. The remaining two blank faces lie opposite to each other. Clearly, in the cube shown in fig. (1), the face consisting of the four symbols is not the same as that formed (as shown above). Hence, the cube in fig. (1) cannot be formed

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Filed Under: Cubes and Dice
Exam Prep: Bank Exams , CAT
Job Role: Bank Clerk , Bank PO

23 22720
Q:

In a class of 78 students 41 are taking French, 22 are taking German. Of the students taking French or German, 9 are taking both courses. How many students are not enrolled in either course?

A) 6 B) 12
C) 24 D) 18
 
Answer & Explanation Answer: C) 24

Explanation:

You could solve this by drawing a Venn diagram. A simpler way is to realize that you can subtract the number of students taking both languages from the numbers taking French to find the number taking only French. Likewise find those taking only German. Then we have:Total = only French + only German + both + neither

78 = (41-9) + (22-9) + 9 + neither.

Not enrolled students = 24

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Filed Under: Average
Exam Prep: GRE

20 22710
Q:

Arrange the following words as per order in the dictionary.

1. Preach
2. Praise
3. Precinet
4. Precept
5. Precede

A) 2, 1, 5, 4, 3 B) 2, 1, 3, 4, 5
C) 2, 5, 1, 4, 3 D) 1, 2, 5, 4, 3
 
Answer & Explanation Answer: A) 2, 1, 5, 4, 3

Explanation:
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Filed Under: Logical Sequence of Words
Exam Prep: Bank Exams

0 22709
Q:

I.  Apartments in the Riverdale Manor cost less than apartments in The Gaslight Commons.

II. Apartments in the Livingston Gate cost more than apartments in the The Gaslight Commons.

III.Of the three apartment buildings, the Livingston Gate costs the most.

If the first two statements are true, the third statement is

A) true B) false
C) uncertain D) none
 
Answer & Explanation Answer: A) true

Explanation:

Since the Gaslight Commons costs more than the Riverdale Manor and the Livingston Gate costs more than the Gaslight Commons, it is true that the Livingston Gate costs the most.

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Filed Under: Logic

33 22699
Q:

In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected such that at least one boy should be there?

A) 209 B) 290
C) 200 D) 208
 
Answer & Explanation Answer: A) 209

Explanation:

We may have (1 boy and 3 girls) or (2 boys and 2 girls) or (3 boys and 1 girl) or (4 boys). 

 

Required number of ways = 6C1*4C3+6C2*4C2+6C3*4C1+6C4  

= 6C1*4C1+6C2*4C2+6C3*4C1+6C2 = 209.

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Filed Under: Permutations and Combinations

11 22696
Q:

A letter is takenout at random from 'ASSISTANT'  and another is taken out from 'STATISTICS'. The probability that they are the same letter is :

A) 35/96 B) 19/90
C) 19/96 D) None of these
 
Answer & Explanation Answer: B) 19/90

Explanation:

ASSISTANT→AAINSSSTT

STATISTICS→ACIISSSTTT

Here N and C are not common and same letters can be A, I, S, T. Therefore

 Probability of choosing A =  2C19C1×1C110C1 = 1/45 

 Probability of choosing I = 19C1×2C110C1 = 1/45

Probability of choosing S = 3C19C1×3C110C1 = 1/10

Probability of choosing T = 2C19C1×3C110C1 = 1/15

Hence, Required probability =   145+145+110+115= 1990 

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Filed Under: Probability
Exam Prep: AIEEE , Bank Exams , CAT , GATE
Job Role: Bank Clerk , Bank PO

97 22692
Q:

In a race of 1000 meters, A can beat B by 100 meters, in a race of 800 meters, B can beat C by 100 meters. By how many meters will A beat C in a race of 600 meters?

A) 125.5 meters B) 126.5 meters
C) 127.5 meters D) 128.5 meters
 
Answer & Explanation Answer: C) 127.5 meters

Explanation:

When A runs 1000 meters, B runs 900 meters and when B runs 800 meters, C runs 700 meters.

Therefore, when B runs 900 meters, the distance that C runs = (900 x 700)/800 = 6300/8 = 787.5 meters.

So, in a race of 1000 meters, A beats C by (1000 - 787.5) = 212.5 meters to C.

So, in a race of 600 meters, the number of meters by Which A beats C = (600 x 212.5)/1000 = 127.5 meters.

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Filed Under: Races and Games

30 22687
Q:

By mixing two qualities of pulses in the ratio 2: 3 and selling the mixture at the rate of Rs 22 per kilogram, a shopkeeper makes a profit of 10 %. If the cost of the smaller quantity be Rs 14 per kg, the cost per kg of the larger quantity is:

A) Rs 23 B) Rs 25
C) Rs 24 D) Nonof these
 
Answer & Explanation Answer: C) Rs 24

Explanation:

Cost Price of 5 kg = Rs.(14*2 + x*3) = (28 + 3x).

Sell price of 5 kg = Rs. (22x5) = Rs. 110.

[{110 - (28 + 3x)}/(28 + 3x) ]* 100 =10

[82-3x/28 + 3x]= 1 / 10

820 - 30x = 28 +3x 

33x = 792 

x = 24

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Filed Under: Profit and Loss

59 22674