Q:
      
      
         
            
Four dice are thrown simultaneously. Find the probability that two of them show the same face and remaining two show the different faces.
         
       
      
      
      
          
      
      
          Answer & Explanation
         Answer: B) 5/9         
         
Explanation: Select a number which ocurs on two dice out of six numbers (1, 2, 3, 4, 5, 6). This can be done in , ways.
 
Now select two distinct number out of remaining 5 numbers which can be done in  ways. Thus these 4 numbers can be arranged in 4!/2! ways.
 
So, the number of ways in which two dice show the same face and the remaining two show different faces is 
 
 =>  n(E) = 720
 
       
      
      
      
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